문제
Write a query that prints a list of employee names (i.e.: the name attribute) for employees in Employee having a salary greater than per month who have been employees for less than months. Sort your result by ascending employee_id.
Input Format
The Employee table containing employee data for a company is described as follows:
where employee_id is an employee's ID number, name is their name, months is the total number of months they've been working for the company, and salary is the their monthly salary.
Sample Input
Sample Output
Angela Michael Todd Joe
Explanation
Angela has been an employee for month and earns per month.
Michael has been an employee for months and earns per month.
Todd has been an employee for months and earns per month.
Joe has been an employee for months and earns per month.
We order our output by ascending employee_id.
코드
SELECT name
FROM Employee
WHERE salary > 2000
AND months < 10
ORDER BY employee_id
풀이
- Employee 테이블에서 name 컬럼만 조회
- salary가 2000 초과
- months가 10달 미만
- employee_id 오름차순 정렬
'Algorithm > MySQL' 카테고리의 다른 글
[해커랭크(HackerRank)] Weather Observation Station 15 (MySQL) (0) | 2021.06.28 |
---|---|
[해커랭크(HackerRank)] Higher Than 75 Marks (MySQL) (0) | 2021.06.28 |
[해커랭크(HackerRank)] Employee Names (MySQL) (0) | 2021.06.28 |
[해커랭크(HackerRank)] Weather Observation Station 12 (MySQL) (0) | 2021.06.28 |
[해커랭크(HackerRank)] Weather Observation Station 6 (MySQL) (0) | 2021.06.28 |